0.56x^2-5x+0.2=0

Solution for 0.56x^2-5x+0.2=0 equation:

0.56x^2-5x+0.2=0

a = 0.56; b = -5; c = +0.2;
Δ = b2-4ac
Δ = -52-4·0.56·0.2
Δ = 24.552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{24.552}}{2*0.56}=\frac{5-\sqrt{24.552}}{1.12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{24.552}}{2*0.56}=\frac{5+\sqrt{24.552}}{1.12}
$